Electrostatics MCQs for MDCAT Practice
Physics section, Electrostatics chapter. Up to eight free sample questions, each with the correct answer and a worked explanation. The full chapter opens in the app.
The bank has 1,352 active questions on this chapter. Your first 500 practice attempts are free, and every attempt includes a worked explanation.
- Question 1The force of repulsion between two charges is considered as:
- -ve
- May be +ve or -ve
- Cannot be predicted
- +ve (correct answer)
Correct answer: DRepulsive electrostatic forces are always positive, indicating outward push, while attractive forces are negative, signifying inward pull. - Question 2Electric field lines never cross each other. Why?
- ecause electric field lines are always straight and cannot bend. (correct answer)
- ecause electric field lines are imaginary and do not physically exist.
- ecause at the point of crossing, the electric field would have two different directions, which is impossible.
- ecause electric field lines can cross if the charges are equal in magnitude.
Correct answer: AElectric field lines represent the direction of the electric force on a positive test charge; their non-crossing nature ensures a unique field direction at every point. - Question 3The units of the electric field are:
- JC^(-1)
- JC
- Jm^(-1)
- JC^(-1)m^(-1) (correct answer)
Correct answer: DMaster the units of electric field by relating it to work done per unit charge and force per unit charge, ensuring you can derive and recognize equivalent SI units. - Question 4A parallel plate air capacitor has a capacity of 2 pF. If the separation between its plates is doubled and a mica sheet is introduced between its plates, Its capicity becomes 6 pF. What Is the dielectric constant of mica?
- 6 (correct answer)
- 5
- 4
- 3
Correct answer: AThis question tests understanding of how capacitance changes with plate separation and the introduction of a dielectric material in a parallel plate capacitor. - Question 5Two plates are 2cm apart, a potential difference of 10 volt is applied between them, the electric field between the plates is:
- 20 N/C
- 500N/C (correct answer)
- 5 N/C
- 250 N/C
Correct answer: BThis question tests the relationship between electric field, potential difference, and distance between parallel plates, a fundamental concept in electrostatics. - Question 6The negative of the potential gradient is equal to:
- Electric field intensity (correct answer)
- Electric flux
- Magnetic intensity
- Magnetic flux
Correct answer: AThe negative potential gradient directly defines the electric field intensity, a fundamental relationship in electrostatics. - Question 7Two similar charges each of one coulomb placed in the air one meter apart repel each other with a force:
- 9×109 N (correct answer)
- 9.2×104 N
- 9×108 N
- 9×1010 N
Correct answer: AThis question tests the application of Coulomb's Law to calculate electrostatic force between two point charges. - Question 8State some similarities and some differences between electric fields and gravitational fields.
- oth fields are conservative and obey the inverse square law, but only electric fields can be repulsive. (correct answer)
- oth fields are conservative and obey the inverse square law, but only gravitational fields can be repulsive.
- oth fields are conservative and obey the inverse square law, but only gravitational fields can be attractive.
- oth fields follow an inverse square law, but only electric fields can be attractive or repulsive.
Correct answer: AElectric and gravitational fields share similarities in being force fields and obeying inverse-square laws but differ in charge/mass dependence, attraction/repulsion, and relative strength.
Practise all 1,352 Electrostatics questions
A free account keeps your correct, incorrect and unseen questions separate, and shows the explanation after every attempt.
Create a free accountRead the full Electrostatics chapter notes: Electrostatics notes. Or browse every chapter.