Thermodynamics MCQs for MDCAT Practice
Physics section, Thermodynamics chapter. Up to eight free sample questions, each with the correct answer and a worked explanation. The full chapter opens in the app.
The bank has 1,129 active questions on this chapter. Your first 500 practice attempts are free, and every attempt includes a worked explanation.
- Question 1Substances A and B have the same freezing and boiling points. If solid samples of bothsubstances are heated in the exact same way, substance A boils before substance B.Which of the following would NOT explain this phenomenon?
- Substance B has a higher specific heat.
- Substance B has a higher heat of vaporization.
- Substance B has a higher heat of fusion.
- Substance B has a higher internal energy. (correct answer)
Correct answer: DSubstance A boils before B despite same phase transition points, implying differences in energy required for phase changes or temperature increase. - Question 2The efficiency of a Carnot engine increases when:
- The temperature of the cold reservoir increases
- The temperature of the hot reservoir decreases
- The temperature difference between reservoirs increases (correct answer)
- The pressure of the gas increases
Correct answer: CA Carnot engine's efficiency is maximized by a larger temperature difference between its hot and cold reservoirs. - Question 3Choose the correct statement?
- Adiabat is steeper than isotherm (correct answer)
- Isotherm is steeper than isochor
- Isobar is steeper than isotherm
- Adiabat is steeper than isochor
Correct answer: ACompares the slopes of different thermodynamic processes (isotherm, adiabat, isochor, isobar) on a P-V diagram to understand their relative steepness. - Question 4The internal energy change of a gas in an isobaric process is given by:
- nCvΔT (correct answer)
- nCpΔT
- PΔV
- Zero
Correct answer: AInternal energy change () depends on heat capacity at constant volume (), not constant pressure (), even in an isobaric process. - Question 5In which of the following conditions, does the thermodynamic system DOES NOT perform any work?
- Adiabatic condition
- Isochoric condition (correct answer)
- Isobaric condition
- Isothermal condition
Correct answer: BWork done by a thermodynamic system requires a change in volume. Isochoric processes maintain constant volume, thus zero work. - Question 6A Cu rod and a steel rod maintain a constant difference in their lengths constant = 10 cm at all temperatures. If their coefficients of expansion are 1.6 × 10–5 K–1 and 1.2 × 10–5 K–1, then the length of the Cu rod is:
- 40 cm
- 30 cm (correct answer)
- 32 cm
- 24 cm
Correct answer: BThis question tests understanding of thermal expansion and how differential expansion can maintain a constant length difference between two rods. - Question 7During adiabatic compression work done is equal to 200 J. What will be the change in internal energy?
- -200 J
- +200 J (correct answer)
- 100 J
- 0 J
Correct answer: BAdiabatic compression: Work done on gas increases its internal energy. This MCQ tests the First Law of Thermodynamics under adiabatic conditions. - Question 8A gas expands adiabatically, and its temperature decreases. The work done is:
- Zero
- Positive (correct answer)
- Negative
- Equal to heat supplied
Correct answer: BAdiabatic expansion causes temperature drop and work done by the gas. The First Law of Thermodynamics dictates work sign in such processes.
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